We have 420Ah of battery, a 1500 watt air fryer and a 2000 watt inverter. Running the fryer for 20 mins reduced the battery by 5%.
I'm interested to see how the figures stack up.
So running the fryer for an hour would equal 1500Wh, so for 20 min that's 500Wh.
To convert to Ah, we divide by volts, (12?) to give 42 Ah, which is 10% of the battery, not 5%.
I realise that the fryer would turn itself on and off during the 20 mins, but it would only have to be on half the time. And then there is the inefficiency of the inverter to take into account.
So I wonder if someone could tell me if I'm in the right ballpark with these all of this? Or way out
I'm interested to see how the figures stack up.
So running the fryer for an hour would equal 1500Wh, so for 20 min that's 500Wh.
To convert to Ah, we divide by volts, (12?) to give 42 Ah, which is 10% of the battery, not 5%.
I realise that the fryer would turn itself on and off during the 20 mins, but it would only have to be on half the time. And then there is the inefficiency of the inverter to take into account.
So I wonder if someone could tell me if I'm in the right ballpark with these all of this? Or way out